find the orbit of 332 cm
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Answer:
According to de Broglie’s equation,
λ = h/mv
Where,
λ = wavelength associated with the electron
h = Planck’s constant
m = mass of electron
v = velocity of electron
Substituting the values in the expression of λ:
λ = 6.626x10-34 / (9.11x10-31)(2.19x106)
=3.32x10-10
= 332 pm
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