Question

Find the order and degree of the D.E's

Question = [(dy/dx)¹/² + (d²y/dx²)¹/³]¹/⁴ = 0

Answer 1

Hello,

In the given question
[(dy/dx)¹/² + (d²y/dx²)¹/³]¹/⁴ = 0

Take power 4 both the sides

[(dy/dx)¹/² + (d²y/dx²)¹/³] = 0

(dy/dx)¹/² = - (d²y/dx²)¹/³

take power 6 both the sides

(dy/dx)^3= - (d²y/dx²)^2

(dy/dx)^3 + (d²y/dx²)^2 = 0

Now you can easily see that eq has

Order= 2 and degree 2.

Hope it helps you