Question

find the order of magnitude of mass of sun where mass of sun is 1.991×10^30 kg​

Answer 1

Answer:

The free-body diagram (part a) is shown at the right.

The acceleration of the car can be computed as follows:

a = v2/R = (18.0 m/s)2/(12.0 m) = 27.0 m/s2 (part b)

The net force can be found in the usual manner:

Fnet = m•a = (500. kg)•(27.0 m/s2) = 13500 N (part b)

Since the center of the circle (see diagram) is above the riders, then both the net force and the acceleration vectors have an upward direction. The force of gravity is downwards, so the net force is equal to the upward force minus the downward force:

Fnet = Fnorm - Fgrav

where Fgrav = m • g = (500. kg) • (9.8 m/s/s) = 4900 N

Thus,

Fnorm = Fnet + Fgrav = 13500 N + 4900 N = 18400 N (part c)

Answer 2

Answer:

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Explanation:

Order of the magnitude is given by the power of 10 in any quantity.

(a) Acceleration due to gravity,g=9.81m/s2

So, order is 100

(b) Gravitational constant, G=6.67×10−11Nm2Kg−1

So, order is 10−11

(c) The period of rotation of the earth about its own axis is

So, order is 23hrs56mins4secs=86164sec

 8.61∗104 sec