Question

Find the order of magnitude of the mass of the moon whose radius is 3.84*106m and average density is 4*10^3 kg m-3 [mass=volume*density]

Answer 1

If it is NCERT question then the r is 3.84*10^6m

Formula Given:
Mass= volume * density

Given data:
r=3.84*10^6 m 
we, have to apply sphere formula here.                [moon is spherical]
V= 4/3 * π * r³
V= 4/3 * π * (3.84*10^6m)³
Then mass= 4/3 * π *  (3.84*10^6m)³ * 4*10³ kg/m³
⇒948.729 * 10^21 kg


Hence the mass is 948.729 * 10^21 kg.

Answer 2

Answer:

no this answer should be 10 to the power of +24 kgs