Find the order of magnitude of the mass of the moon whose radius is 3.84*106m and average density is 4*10^3 kg m-3 [mass=volume*density]
Answers
Answered by
8
If it is NCERT question then the r is 3.84*10^6m
Formula Given:
Mass= volume * density
Given data:
r=3.84*10^6 m
we, have to apply sphere formula here. [moon is spherical]
V= 4/3 * π * r³
V= 4/3 * π * (3.84*10^6m)³
Then mass= 4/3 * π * (3.84*10^6m)³ * 4*10³ kg/m³
⇒948.729 * 10^21 kg
Hence the mass is 948.729 * 10^21 kg.
Formula Given:
Mass= volume * density
Given data:
r=3.84*10^6 m
we, have to apply sphere formula here. [moon is spherical]
V= 4/3 * π * r³
V= 4/3 * π * (3.84*10^6m)³
Then mass= 4/3 * π * (3.84*10^6m)³ * 4*10³ kg/m³
⇒948.729 * 10^21 kg
Hence the mass is 948.729 * 10^21 kg.
Answered by
9
Answer:
no this answer should be 10 to the power of +24 kgs
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