Question

find the ordinate of a point whose abscissa is 10 and which is at a distance of 10 units from the point P(2,-3).

Answer 1

let y is the ordinate of unknown point
(10,y)
a/c question
distance between points=10
√{(10-2)^2+(y+3)^2}=10
squaring both sides
64+(y+3)^2=100

(y+3)^2=(6)^2

take square root both sides

y+3=+_6

y=-3+_6
=-9 and 3

Answer 2

Answer:

The ordinate of a point whose abscissa is 10 and which is at a distance of 10 units from the point P(2,-3).