Math, asked by isauduiqsdiqw, 4 months ago

Find the orthocenter of the triangle whose vertices are A (-2, -1) B (6, -1) and C (2, 5)

Answers

Answered by bittumogatalareddy
1

Answer:

Let the circumcentre be

(

x

,

y

)

A

(

8

,

6

)

,

B

(

8

,

2

)

,

C

(

2

,

2

)

S

A

=

S

B

=

S

C

=

R

So

S

A

=

S

B

(

8

x

)

2

+

(

6

y

)

2

=

(

8

x

)

2

+

(

2

y

)

2

x

2

+

y

2

+

64

+

36

16

x

12

y

=

x

2

+

y

2

16

x

+

4

y

+

64

+

4

100

=

16

y

+

68

y

=

2

Similiarly

S

B

=

S

C

(

8

x

)

2

+

(

2

y

)

2

=

(

2

x

)

2

+

(

2

y

)

2

x

2

+

y

2

16

x

+

4

y

+

64

+

4

=

x

2

+

y

2

4

y

4

x

+

8

12

x

=

60

x

=

5

So circumcenter SA=

(

8

5

)

2

+

(

6

2

)

2

=

5

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