find the orthocentre of the traingle whose vertices are (-2,-1),(6,-1) and (2,5)
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Step-by-step explanation:
A(–2, –1) B(6, –1), C(2, 5) are the vertices of ∆ABC Slope of BC = (5 + 1)/ (2 - 6) = 6/- 4 = - 3/2 AD is perpendicular to BC Slope of AD = 2/3 Equation of AD is y + 1 = 2/3 (x + 2) 2x – 3y + 1 = 0 —— (1) Slope of AC = (5 + 1)/ (2 + 2) = 6/4 = 3/2 Slope of BE = – 2/3 Equation of BE is y + 1 = – 2/3 (x – 6) 2x + 3y – 9 = 0 —— (2) By solving (1), (2)
∴ Co-ordinates of the ortho centre O are = [2, 5/3]
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