find the orthocentre of the triangle formed by lines 7x+y-10,x-2y+5=0,x+y+2=0
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Answer:
(- 2/3, 4/3)
Step-by-step explanation:
Given lines are 7x + y – 10 = 0 → (1), x – 2y + 5 = 0 → (2), x + y + 2 = 0 → (3) Point of intersection of (2) and (3) is B (–3, 1). Equation of the altitude through B is (x + 3) – 7(y – 1) = 0 ⇒ x – 7y + 10 = 0 → (4) Point of intersection of (3) and (1) is C(2, –4) Equation of the altitude through C is 2(x – 2) + (y + 4) = 0 ⇒ 2x + y = 0 → (5) Solving (4) and (5), orthocenter is (- 2/3, 4/3)
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Find the ortho center of the traingle formed by the lines 7x+y-10=0,x-2y+5=0,x+y+2=0 find the answer
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