find the orthocentre of triangle whose vertices are (5 ,- 2) (-1, 2)and (1, 4)
Answers
Answered by
1
Answer:
use vertics foormula 1/2 [x1 (y2-y3)+x2(y3-y2)+x3(y2-y2)
Answered by
4
Step-by-step explanation:
A(5,-2), B(-1,2), C(1,4)
x1=5, x2=-1, x3=1, y1=-2, y2=2, y3=4
Now,
Orthocentre of triangle =x1+x2+x3/3, y1+y2+y3/3
=[5+(-1)+1] /3, [(-2)+2+4] /3
=5/3, 4/3
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