Question

find the other. Divide the sum of -2/5 and 9/-10 by the sum of 3/7 and 4/5.

HLEP PLEASE ​

Answer 1

We have to divide the sum of $-2/5\ and\ 9/-10$ by the sum of $3/7 \ and\ 4/5.$

By using the Bodmas rule, we are solving the above equation.

As we know that the Bodmas rule is used to remember the order of operations to be followed while solving expressions in mathematics.

Where,

$\begin{array}{l}\mathrm{B}=\text{brackets}\\\mathrm{O}=\text { order of powers or rules } \\\mathrm{D}=\text { division } \\\mathrm{M}=\text { multiplication } \\\mathrm{A}=\text { addition } \\\mathrm{S}=\text { subtraction }\end{array}$

We are solving in the following way:

We have,

The sum of $-2/5\ and\ 9/-10$will be:

$\Rightarrow -\frac{2}{5} +(-\frac{9}{10} )\\\\\Rightarrow -\frac{2}{5} -\frac{9}{10} \\\\\Rightarrow \frac{-13}{10}$

Now, the sum of $3/7 \ and\ 4/5$will be:

$\Rightarrow \frac{3}{7} +\frac{4}{5} \\\\\Rightarrow \frac{43}{35}$

Dividing the sum of $-2/5\ and\ 9/-10$ by the sum of $3/7 \ and\ 4/5.$

$\Rightarrow \frac{-13}{10} /\frac{43}{35} \\\\\Rightarrow \frac{-13}{10} \times\frac{35}{43} \\\\\Rightarrow -\frac{91}{86}$

Hence, the solution of the above equation is$-\frac{91}{86}$.

Answer 2

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