Question

find the other trigonometric ratios given that tan teta= 2mn/m^-n^​

Answer 1

Step-by-step explanation:

if tan theta is = 2mn / (m^2 - n^2)

sin theta / cos theta = 2mn / (m^2-n^2)

on comparing these equations

sin theta = 2mn

cos theta = (m^2 - n^2 )

cosec theta = 1 / sin theta

= 1 / 2mn

sec theta = 1 / cos theta

= 1 / (m^2 - n^2)

cot theta = 1 / tan theta

= 1/ (2mn / (m^2 - n^2)

= (m^2 - n^2) / 2mn

HOPE IT HELPS .

Answer 2

Answer:

Step-by-step explanation:

if tan theta is = 2mn / (m^2 - n^2)

sin theta / cos theta = 2mn / (m^2-n^2)

on comparing these equations

sin theta = 2mn

cos theta = (m^2 - n^2 )

cosec theta = 1 / sin theta

= 1 / 2mn

sec theta = 1 / cos theta

= 1 / (m^2 - n^2)

cot theta = 1 / tan theta

= 1/ (2mn / (m^2 - n^2)

= (m^2 - n^2) / 2mn