find the other trigonometric ratios given that tan teta= 2mn/m^-n^
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Answered by
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Step-by-step explanation:
if tan theta is = 2mn / (m^2 - n^2)
sin theta / cos theta = 2mn / (m^2-n^2)
on comparing these equations
sin theta = 2mn
cos theta = (m^2 - n^2 )
cosec theta = 1 / sin theta
= 1 / 2mn
sec theta = 1 / cos theta
= 1 / (m^2 - n^2)
cot theta = 1 / tan theta
= 1/ (2mn / (m^2 - n^2)
= (m^2 - n^2) / 2mn
HOPE IT HELPS .
Answered by
1
Answer:
Step-by-step explanation:
if tan theta is = 2mn / (m^2 - n^2)
sin theta / cos theta = 2mn / (m^2-n^2)
on comparing these equations
sin theta = 2mn
cos theta = (m^2 - n^2 )
cosec theta = 1 / sin theta
= 1 / 2mn
sec theta = 1 / cos theta
= 1 / (m^2 - n^2)
cot theta = 1 / tan theta
= 1/ (2mn / (m^2 - n^2)
= (m^2 - n^2) / 2mn
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