find the other two member of Pythagorean triplet one of whose member is 26
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by this method (2m,m^2-1m^2+1)
one no 26 =2m=26
then 26÷2 = 13=m
other two numbers are m^2+1=13^2+1= 169+1=150
M2-1=13^2-1 =169-1 = 168 show other two numbers are 150 and 168 the triplets 26, 150 and 168
one no 26 =2m=26
then 26÷2 = 13=m
other two numbers are m^2+1=13^2+1= 169+1=150
M2-1=13^2-1 =169-1 = 168 show other two numbers are 150 and 168 the triplets 26, 150 and 168
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