Find the other two members of pythagorean triplet if one member is 7
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Answer:
let n=7
formula is -
(n square - 1)(n square+1)and (n)
therefore,
(n square-1)
=7 square-1
=49-1
=48.
(n square+1)
=7 square+1
=49+1
=50.
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