Find the other two members of pythagorean triplet if one member is 8
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For every natural number m>1
Pythagorean triplets are 2m, m²+1, m²-1
In which 2m is the smallest member.
2m=8
m= 4
m²+1= 4²+1= 16+1= 17
m²+1=17
m²- 1= 4²-1= 16-1= 15
m²-1= 15
The Pythagorean triplets are 8 ,15 ,17
Pythagorean triplets are 2m, m²+1, m²-1
In which 2m is the smallest member.
2m=8
m= 4
m²+1= 4²+1= 16+1= 17
m²+1=17
m²- 1= 4²-1= 16-1= 15
m²-1= 15
The Pythagorean triplets are 8 ,15 ,17
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