Question

find the other two members of the py t h a g o r e a n t r i p l e t whose smallest number is 18​

Answer 1

Answer:

required pythagorean triplet ( 18,80,82)

Step-by-step explanation:

$pythgorean \: triplet \: (2m \: {m}^{2} - 1 \: {m}^{2} + 1)$

smallest number = 2m= 18

m= 9

${m}^{2} - 1 = {9}^{2} - 1 = 80$

${m}^{2} + 1 = {9}^{2} + 1 = 82$

required pythagorean triplet ( 18,80,82)