find the other two sides of a right angled triangle whose shorter side is 6cm long. the sides of it are in A.P
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Answer:
Step-by-step explanation:
It's being given that, in a right angled triangle the shorter side is 6 cm.
And, the other two sides are in AP.
Let, the other sides are (6+d) and (6+2d).
Where, d is common difference.
Therefore, the longer side will be the hypotenus.
Therefore, hypotenus = (6+2d) cm
Now, by pythagoras theorem, we have,
But, if d = -6
=> 6 + d = 6 - 6 = 0
Which can't be possible.
Therefore, d = 2.
Therefore, other sides = (6+2) and (6+4)
Hence, the required sides are 8 cm and 10 cm.
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