Question

find the other two sides of right angled triangle who's hypotenuse is, 10√2​

Answer 1

Required Answer :

The other two sides of the right angled triangle whose hypotenuse is 10√2 units is :-

• Base = 10 units
• Perpendicular = 10 units

Given :

Hypotenuse of a right angled triangle = 10√2 units

To find :

The other two sides of the right angled triangle

Solution :

Let :-

The other two sides of the right angled triangle be x units.

• Base = x units
• Perpendicular = x units

Using pythagoras theorem,

Pythagoras theorem states that in a right - angled triangle, the sum of the square of the hypotenuse is equal to the sum of the square of the other two sides, i.e. the perpendicular and the base.

Mathematically,

• H² = P² + B²

where,

• H denotes the hypotenuse
• P denotes the perpendicular
• B denotes the base

Substituting the given values :-

→ (10√2)² = (x)² + (x)²

→ 10√2 × 10√2 = x² + x²

→ 100 × 2 = x² + x²

→ 200 = 2x²

→ 200/2 = x²

→ 100 = x²

→ Taking square root on both the sides :-

→ √100 = x

→ √(10 × 10) = x

→ ± 10 = x

→ As we know, the side of the triangle cannot be negative. So, the negative sign will get rejected.

→ ± 10 Reject -ve = x

→ 10 = x

The other two sides of the right angled triangle :-

• Base = x = 10 units
• Perpendicular = x = 10 units