Question

Find the other zero of the quadratic polynomial y +7y-60 if one zero is -12.

Answer 1

p(x) = y^2 +7y-60

One of the zero = -12

therefore, y= -12

therefore, y+12=0

f(x) = y+12

therefore to find another zero we have to divide p(x) by f(x)

therefore,  (y^2+7y-60)/(y+12)

                 = y-5

as y-5 is a zero of the polynomial

therefore, y-5=0

                 y = 5

therefore, another zero= 5