Math, asked by shubham4437, 1 year ago

find the other zeroes of the following polynomial 5√5x2+30x+8√5

Answers

Answered by misbahsajjid4
0

P(x)=5*root(5)x^2+30x+8*root(5)

Solution

5*root(5)x^2+30x+8*root(5)=0

while splitting middle terms or by using quadratic equation format,

we can get roots of above equation,

either

x=-0.894

or

x=-1.788


so the there are two values of x, that is either -0.894 or -1.788

or we can say that zeros or roots of the following polynomial equation ,

5*root(5)x^2+30x+8*root(5)=0, is

-0.894 or -1.788

Answered by ayushyadav143
0

Answer:

5√5x² + 30x + 8√5

splitting the middle term

= 5√5x² + 20x + 10x + 8√5

= 5√5x² + 4 × 5x + (2√5 ) × √5 x + 2√5 × 4

= 5x ( √5x + 4 ) + ( 2√5 ) [ √5x + 4 ]

= ( √5x + 4 ) ( 5x + 2√5 )

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