find the other zeroes of the polynomial
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Let the zeroes be √2 and -√2
(x + √2)(x-√2)=x-2
by long division method
x^4-5x^3+2x^2+10x-8 is divided by x^2-2
then we will get the quotient as
x^2-5x+4
then by middle term splitting
we get
(x-4)(x+1)
ie, x=4,x=1
therefore the remaining zeroes are
√2,-√2,4 and 1
thank you
(x + √2)(x-√2)=x-2
by long division method
x^4-5x^3+2x^2+10x-8 is divided by x^2-2
then we will get the quotient as
x^2-5x+4
then by middle term splitting
we get
(x-4)(x+1)
ie, x=4,x=1
therefore the remaining zeroes are
√2,-√2,4 and 1
thank you
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