Question

Find the other zeros of quadratic polynomial x^3-8x^2+19x-12 if it's one zero is x=1

Answer 1

Answer:

The other zeros are 3 and 4.

Step-by-step explanation:

x=1 is a root => (x-1) is a factor

Divide x³ - 8x² + 19x - 12 by x-1 (or just equate coefficients) to get:

x³ - 8x² + 19x - 12 = ( x - 1 ) ( x² - 7x + 12 )

Factorizing the quadratic, we get

x³ - 8x² + 19x - 12 = ( x - 1 ) ( x - 3 ) ( x - 4 )

Therefore.

f(x) = 0  <=>  x = 1, 3 or 4.

Answer 2

Answer is in the attachment