Question

find the other zeros of the polynomial x power 4 minus 5 x cube + 2 X square + 10 x minus 8 if it is given that two of its zeros are minus root 2 on root 2​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

The other zeroes of the polynomial $x^{4} - 5x^{3} + 2x^{2} + 10x - 8$ are 4, 1.

• Given,

$\sqrt{2}, - \sqrt{2}$ are roots of polynomial.

• Factorizing the polynomial, we get

             $x^{2} - 5x + 4\\x^{2} - (4+1)x + (4)(1)\\comparing with x^{2} - (a+b)x+ab, where a, b are roots of polynomial, we get\\a = 4, b = 1\\Therefore, the remaining roots are 4, 1$

Please refer attachment.