Find the other zeros of the polynomial x4-5x3+2x2+10x-8
GuntasDhillon:
u need to give at least one zero
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(x-1) (x-4) (x+√2) (x-√2) are the roots
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Hey Friend ☺
☆ FACTORIZATION ☆
x^4 - 5x^3 + 2x^2 + 10x - 8
》x^4 - 4x^3 - x^3 + 2^2 + 10x - 8
》x^3 ( x - 4 ) - x^3 + 4x^2 - 2x^2 + 10x - 8
》x^3 ( x - 4 ) - x^2 ( x - 4 ) - 2x^2 + 8x + 2x - 8
》x^3 ( x - 4 ) - x^2 ( x - 4 ) - 2x ( x - 4 ) + 2 ( x - 4 )
》 ( x - 4 ) ( x^3 - x^2 - 2x + 2 )
》( x - 4 )[ x^2 ( x - 1 ) - 2 ( x - 1 ) ]
》( x - 4 )( x - 1 )( x^2 - 2 )
So the factors of x^4 - 5x^3 + 2x^2 + 10x + 8 are ( x - 4 ) , ( x - 1 ) & ( x^2 - 2 )
Hope it helps you !!
✌
☆ FACTORIZATION ☆
x^4 - 5x^3 + 2x^2 + 10x - 8
》x^4 - 4x^3 - x^3 + 2^2 + 10x - 8
》x^3 ( x - 4 ) - x^3 + 4x^2 - 2x^2 + 10x - 8
》x^3 ( x - 4 ) - x^2 ( x - 4 ) - 2x^2 + 8x + 2x - 8
》x^3 ( x - 4 ) - x^2 ( x - 4 ) - 2x ( x - 4 ) + 2 ( x - 4 )
》 ( x - 4 ) ( x^3 - x^2 - 2x + 2 )
》( x - 4 )[ x^2 ( x - 1 ) - 2 ( x - 1 ) ]
》( x - 4 )( x - 1 )( x^2 - 2 )
So the factors of x^4 - 5x^3 + 2x^2 + 10x + 8 are ( x - 4 ) , ( x - 1 ) & ( x^2 - 2 )
Hope it helps you !!
✌
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