Question

find the outer volume of iron hemisphere cup whose thickness
is 0.5 cm and radius is 4.5​

Answer 1

Answer:

Inner radius, r = 6 cm

Thickness, t = 1 cm

Outer radius, R = 6+1 = 7 cm

Therefore,

Volume of steel required =

3

2

πR

3

−

3

2

πr

3

=

3

2

×

7

22

×7

3

−

3

2

×

7

22

×6

3

=

21

5588

cm

3

Answer 2

Step-by-step explanation:

• 3/4 pi r³
• 3/4 ×22/7 ×4×4×4
• 3×22/7×16
• 48 pi