Question

Find the oxidation no in each-
i Carbon in carbon sub oxidė (C302)
ij Bromin in tribromo octaoxide (Br303)​

Answer 1

Explanation:

Oxidation number of C in C3O2 is

3x - 2*2 = 0

3x = 4

x = + 4/3

Oxidation number of Br3O3 is

3x - 2*3 = 0

3x = 6

x = + 2