Question

find the oxidation no. of S in CuSO4​

Answer 1

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To find the Oxidation Number of Sulphur in $\sf{CuS{O}_{4}}$

First of all,we need to know the oxidation numbers of the others elements :

• Oxidation Number of Copper is + 2

• Oxidation Number of Oxygen is - 2

Since,

There are four atoms of oxygen, the oxidation state would be - 8

Using the relation,

$\huge{ \boxed{\boxed{ \sf{ \green{sum \: of \: all \: o.n \: = \: 0}}}}}$

Let the oxidation number of sulphur be x

Implies,

$\sf{2 + x - 8 = 0} \\ \\ \huge{ \rightarrow \: \sf{x = + 6}}$

Thus,the oxidation of sulphur in given compound is + 6

Answer 2

Answer:

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