Find the oxidation number of carbon in C2H5OH
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C2H5OH We can write it as CH3CH2OH Now let us find the oxidation number of oxidation number of methyl carbon in it is as follows:
1.The oxidation number of ¹H is 1. That of OH⁺ is -1.
2.Thus, the combined oxidation number of all but the C-atoms in the given compound is 5(1)+(-1) = 5–1 = 4. Since the compound given must have an overall oxidation number of 0, i.e. a neutral molecule. The oxidation number of the two carbons together should be -4, giving that of each carbon to be -2.
1.The oxidation number of ¹H is 1. That of OH⁺ is -1.
2.Thus, the combined oxidation number of all but the C-atoms in the given compound is 5(1)+(-1) = 5–1 = 4. Since the compound given must have an overall oxidation number of 0, i.e. a neutral molecule. The oxidation number of the two carbons together should be -4, giving that of each carbon to be -2.
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