find the oxidation number of Cr in Cr(OH)4^-1
Answers
Answered by
6
Answer:
x-4=-1
x=3
Therefore oxidation state of Cr is 3
Answered by
1
The oxidation of Cr in Cr(OH)₄⁻¹ is +3
GIVEN
Chromium Hydroxide ion Cr(OH)₄⁻¹
TO FIND
The oxidation number of chromium in chromium hydroxide ion.
SOLUTION
We can simply solve the above problem as follows
The oxidation number is the value assigned to an atom or compound of an ion that represents its oxidation state in a compound.
We know that,
The sum of oxidation of elements in an ion = Net charge on the ion.
Let, the oxidation number of Chromium be, x
The oxidation number of Oxygen atoms = -2
Oxidation number kr Hydrogen atom = +1.
So,
x + 4(-2+1) = -1
x - 4 = -1
x = -1+4 = 3
Hence, The oxidation of Cr in Cr(OH)₄⁻¹ is +3
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