find the oxidation number of Cr in Na2Cr2O7
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Na = +1 and O = -2 Na2Cr2O7 There are 2 atoms of Na, so 2 (+1) = +2 and there are 7 atoms of O, so 7 (-2) = -14 +2 -14 = -12 The net charge has to be 0, but we have -12. What added to -12 will equal 0? That would be +12. There are 2 Cr atoms, so +12/2 = +6, and that is the charge of Cr. Check to see if you are right: +2 -14 +12 = 0. Yay! So the charge of Cr is +6.
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