Question

find the oxidation number of element 16a​

Answer 1

Answer:

banakkaak

Explanation:

name of the length of its formula is i

Answer 2

Explanation:

Let X be the oxidation number of P in NaH

2

PO

4

. The oxidation numbers of Na, H and O are +1, +1 and −2 respectively.

+1+2(+1)+X+4(−2)=0

3+X+−8=0

X+−5=0

X=+5

The oxidation number of P in NaH

2

PO

4

is +5.