find the oxidation number of MN in KMnO_4
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The oxidation state of Mn in KMnO4 is +7
K Mn O4 - oxidation state of Mn is “x”. So,
(+1) + (x) + (2*(-4)) = 0
x = 7
K Mn O4 - oxidation state of Mn is “x”. So,
(+1) + (x) + (2*(-4)) = 0
x = 7
Answered by
0
7
1+x+4*-2=0
x=7
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1+x+4*-2=0
x=7
mark me as a brainiest answer if you like it
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