Find the oxidation number of Mn in KMnO4.
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Answered by
12
oxidation number
k=1
O=-2
O4=-8
Mn=x
KMnO4
1+x-8=0
x=7
k=1
O=-2
O4=-8
Mn=x
KMnO4
1+x-8=0
x=7
Answered by
8
let the oxidation no of Mn is = X
in KMnO4, k and O have oxidation no +1,-2 respectively and KMnO4 is a stable and uncharged compound, so it's oxidation no will be 0,
so,
+1 + X +(-2)8=0
X-7 = 0
X= +7
Hope this helps you
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