Chemistry, asked by thasneemeasa, 7 months ago

find the oxidation number of Mn is KMnO4 (oxidation number of K is +1, oxidation number of O is -2)

Answers

Answered by seemajadhav

3

Answer:

+7

+1+Mn+4(-2)=0

Mn-7=0

Mn=+7

Answered by DeFier

1

Answer:

The oxidation number of Mn in KMnO4 is +7

Explanation:

No. of Kalium atoms: 1

No. of Manganese atoms: 1

No. of Oxygen atoms: 4

=> 1 + x + 4(-2) = 0

=> 1 + x -8 + 0

=> x -7 = 0

=> x = +7

Therefore, the oxidation state of Mn in Pottasium Permanganate is +7

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