Question

find the oxidation number of the elements in the following compounds.
a)C in CO2.
b)Mn in MnSO4.
c)N in HNO3

Answer 1

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Answer 2

The oxidation number of the elements in the following compounds.

a) The oxidation number of C in CO2 is +4

b) The oxidation number of Mn in MnSO4 is +7

c) The oxidation number of N in HNO3 is +5

• The oxidation number, also known as the oxidation state, is a number assigned to an atom in a chemical compound that represents the number of electrons that the atom has lost or gained in order to form a chemical bond with another atom. The oxidation number is typically represented by a superscripted Roman numeral.

• In general, atoms in their elemental form have an oxidation number of 0. For example, the oxidation number of a neutral oxygen atom is 0.

• When atoms form compounds, they may lose or gain electrons, which results in a change in their oxidation number.

• For example, in the compound CO2, the carbon atom has an oxidation number of +4, which is because it loses 4 electrons to form chemical bond with two oxygen atoms.

To know more about  oxidation visit : https://brainly.in/question/8065330 https://brainly.in/question/14969130

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