Question

Find the oxidation number of the elements which are underlined in the
compounds given below. (Hint. Oxidation number 0 = -2, K = +1)
• K2Cr2O7
• KCrO3

Answer 1

Answer:

• $K_{2}Cr_{2}O_{7}$

    Let x be the oxidation number of Cr is x

    +1×2+2x+(−2)×7=0

    +2+2x+(−2)×7=0

    2x+(−12)=0  

    2x=+12  

    x=2 +12

    x=+6

• $KCrO_{3}$

    +1+Cr+(−2)×3=0  

    +1+Cr+(−6)=0  

    Cr+(−5)=0  

    Cr=+5

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