find the oxidation number / oxidation state
of underline atom in the given molecule on
ion:
KMnO4
Mn-
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To determine the oxidation state of an atom, we will consider it as 'X'. - So to calculate the oxidation state of manganese in KMnO4, we will consider the oxidation state of manganese as 'X'. -We know that the oxidation state of potassium and oxygen are +1 & -2. -Hence, the oxidation of Mn is +7.
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Answer:
To determine the oxidation state of an atom, we will consider it as 'X'. - So to calculate the oxidation state of manganese in KMnO4, we will consider the oxidation state of manganese as 'X'. -We know that the oxidation state of potassium and oxygen are +1 & -2. -Hence, the oxidation of Mn is +7.
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