Math, asked by udaypandu78, 6 months ago

find the oxidation numbers of
1) NaH"P"O4
2) NaH"S"O4
3) Na"B"H4
4) H2"S"2O7
5) K2"mn"O4
with solution​

Answers

Answered by Anonymous
2

Let X be the oxidation number of P in NaH

2

PO

4

. The oxidation numbers of Na, H and O are +1, +1 and −2 respectively.

+1+2(+1)+X+4(−2)=0

3+X+−8=0

X+−5=0

X=+5

The oxidation number of P in NaH

2

PO

4

is +5.

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