find the oxidation numbers of
1) NaH"P"O4
2) NaH"S"O4
3) Na"B"H4
4) H2"S"2O7
5) K2"mn"O4
with solution
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Let X be the oxidation number of P in NaH
2
PO
4
. The oxidation numbers of Na, H and O are +1, +1 and −2 respectively.
+1+2(+1)+X+4(−2)=0
3+X+−8=0
X+−5=0
X=+5
The oxidation number of P in NaH
2
PO
4
is +5.
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