Chemistry, asked by masterbipul22212, 4 hours ago

find the oxidation state of B in NaBH4

Answers

Answered by misssonali2006

1

Answer:

oxidation number of b in nabh4.

...

Hence the oxidation state of boron is +3.

Let the oxidation state of Boron be X.

As the oxidation state of Na is +1 and Hydrogen is -1 because here hydrogen exist as hydride.

Therefore.

X + (+1) + 4(-1) = 0.

X = +3.

Hence the oxidation state of boron is +3.

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