Find the oxidation state of Fe in Fe(H2O)5(NO) SO4
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Answer:
The oxidation state of Fe is (+1)
Explanation:
x + 5×(0) + (+1)×1 + (-2)×1=0
x=+1
NOTE: Here H2O carry no charge, (NO) group carry +1 charge, SO4 group carry -2 charge.
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