Question

find the oxidation State of mn in Mn²o⁷
and ion on this Compound (Mn-25)​

Answer 1

Hi,

In Mn2O7, the oxidation number of O is (-2),

let the oxidation number of Mn be x,

2x+(-2)*7=0  (as it is a neutral molecule)

2x=14,

x=7

The oxidation number of Mn is +7

Hope it helps!

Answer 2

Mn²O⁷ = 2x +7(-2) =0

2x-14 =0

x= 7