Question

Find the oxidation state of the metals in the give compounds.
KMnO4
K2Cr2O7
MnO2
FeCl3
FeCl2
Fe2O3​

Answer 1

When we look at the reaction equation we can see that K2Cr2O7 (Potassium dichromate) released in total 6 electrons (3 electrons each atom) on the other hand FeCl2 (Iron(II)chloride) accepts only one electron. That’s means-

K2Cr2O7 = Potassium dichromate which is Oxidizing agent ( or Cr2O72-)

FeCl2 = Iron(II)chloride which is Reducing agent (or Fe2+)

HCl = Hydrochloric acid (creates acidic environment)