Question

find the oxidised and reduced substance H²S + I ² — 2 HI + S​

Answer 1

Answer:

H2s is oxidised because it removed hydrogen. and l2 is reduced because here hydrogen is added

Answer 2

Explanation:

When hydrogen sulphide reacts with iodine, then sulphur and hydrogen iodide are formed :

• H2S + I2 -> 2HI + S

(i) In this reaction, H2S is changing into S. It means hydrogen is removed from hydrogen sulphide, so we can say that hydrogen sulphide is being oxidised to sulphur.

(ii) In this reaction, I2 is changing into HI. It means hydrogen is being added to iodine, so we can say that iodine is being reduced to hydrogen iodide.

Therefore,

• Chlorine is oxidising agent.
• hydrogen sulphide is reducing agent.

Hence,

Substance oxidised : H2S

Substance reduced : I2

Oxidising agent : I2

Reducing agent : H2S

Additional information -

Oxidation -

• The addition of oxygen
• The removal of hydrogen
• Loss of electron

Reduction -

• The addition of hydrogen
• The removal of oxygen
• Gain of electron