Question

find the p(0),p(1)and p(2)for each of the following polynomials p(y)=y²-y+1
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Answer 1

Answer:

p(0) = 1

p(1) = 1

p(2) = 3

Step-by-step explanation:

we get the answer by substituting 0,1,2 in place of y

Answer 2

Answer:

p(0)=0²-0+1

=0-0+1

=1

so p(0)= 1

p(1)= (1)²-1+1

=1-1+1

1

so p(1)=1

p(2)=(2)²-2+1

=4-2+1

=3

so p(3) = 3