Question

find the p(0),p(1)and p(2)for each of the following polynomials p(y)=y²-y+1

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Answer 1

Answer:

p(0) = 1

p(1) = 1

p(2)=3

Step-by-step explanation:

p(0) = (0)² - 0 + 1  =  1

p(1)  = (1)² -1 + 1 = 1

p(2) = (2)² - 2 + 1 = 4 - 2 + 1 =3

HOPE IT HELPS......

Answer 2

Hey mate !! Here you go :-

p(0)= $(0)^{2}- (0)+1$

= 1

p(1)=$(1)^{2}- (1)+1$

= $1-1+1$

= 1

p(2)=$(2)^{2}- (2)+1$

= 4-2+1

= 2+1

= 3

Hope that helps you..

Please mark as brainliest answer..