Question

find the p(o),p(1) and p(-1) for x^2+2x+1 polynomial. Please give me right solution And do it Fast

Answer 1

Step-by-step explanation: let take p(0)

Here we must substitute 0 in x value

Here polynomial is x^2+2x+1

P(0) =0^2+2*0+1

=0+0+1

= 1

P(1) =1^2+2*1+1

=1+2+1

=4

P(-1)= (-1)^2+2*(-1)+1

= 1+(-2) +1

= 1-2+1

= 0