Chemistry, asked by vasavinancharla, 7 months ago

Find the p" of 0.05M Ba(OH), aqueous solution.​

Answers

Answered by nallisravankumar
1

Answer:

Answer:- (B) 13

Ba(OH) 2 longrightarrow Ba^ +2 +2OH^ -

.. [OH^ - ]=0.05*2=0.10M

> pOH=-log(0.10)=1

As we know that,

pH + pOH = 14

pH=14-pOH=14-1=13

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