Find the p" of 0.05M Ba(OH), aqueous solution.
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Answer:- (B) 13
Ba(OH) 2 longrightarrow Ba^ +2 +2OH^ -
.. [OH^ - ]=0.05*2=0.10M
> pOH=-log(0.10)=1
As we know that,
pH + pOH = 14
pH=14-pOH=14-1=13
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