Question

find the p(x) who's sum of zero is 9 products of zero 18 find its zero​

Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanation:

Let the 2 zeroes be Alpha and Beta

So given that Alpha+Beta = 9

Alpha*Beta=18

So, we know that

x^2-(Alpha+Beta)x+ (Alpha*Beta)

= x^2-9x+18  

is the required Quadratic Equation.

Things to Remember

The Nominal form of Quadratic Equation is

x^2-(Alpha+Beta)+(Alpha*Beta)

Alpha+Beta= -b/a

Alpha*Beta= c/a

If we need to find the zeroes in this,

x^2-9x+18

By Middle Term Factorisation

x^2-3x-6x+18

=x(x-3)-6(x-3)

=(x-6)(x-3)

x= 6,3

So Alpha = 6

Beta = 3