find the pairs of natural numbers whose least common multiple is 78 and the greatest divisor is 13
Answers
Answered by
10
Answer:
26 and 39
Step-by-step explanation:
For any natural number a and b
a × b = HCF ( a,b ) × LCM ( a,b )
Here LCM = 78 and HCF = 13
therefore 78 × 13 = 1014 = 2 × 3 × 13 × 13
therefore 13 is the HCF
it should be the multiple of both the numbers
a × b = 2×13 × 3×13 = 26×39
Hence the pair of numbers whose HCF is 13 and LCM is 78 are 26 and 39
Answered by
21
Answer:
HII, IN THE ABOVE IMAGE IS THE ANSWER
ANSWER =(26,39)
Step-by-step explanation:
SOLVED IN THE ABOVE TAG.
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