find the parabola whose focus is 1,-1 and vertex is 2,1
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Focus is at S(1,-1)
Vertex is A(2,1)
Let the directrix be MZ and let coordinates of Z be (a,b)
Let the axis of parabola intersects directrix of parabola at Z.
Since, vertex is in between focus and directrix.
⇒
2
a+1
=2;
2
b−1
=1
⇒a=3,b=3
Let P(x,y) be any point on the parabola such that
PS=PM
PS
2
=PM
2
⇒(x−1)
2
+(y+1)
2
=
5
(x+2y−9)
2
⇒4x
2
+y
2
−4xy+8x+46y−71=0
Length of latus rectum =2(Distance between focus and directrix)
=2(
4
2
+2
2
)
=2(2
5
)=4
5
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