Question

find the parameter rectangle bwn who length is 20 m 50 cm and breadth is 12 metre 20 cm​

Answer 1

Step-by-step explanation:

perimeter of rectangle = 20.5+ 12.2

=32.7 m

Answer 2

Question should be:

• find the perimeter of a rectangle whose length is 20 m 50 cm and breadth is 12m 20 cm.

ANSWER:

• Perimeter of the rectangle = 65.4 m

GIVEN:

• Length of rectangle = 20 m 50 cm
• Breadth of rectangle = 12 m 20 cm

TO FIND:

• Perimeter of the rectangle.

SOLUTION:

Perimeter of rectangle = 2(length + Breadth)

Length (in meters) = 20 m + 50/100 = 20.5 m

Breadth (in meters ) = 12 m + 20/100 = 12.2 m

=> Perimeter = 2(20.5+12.2)

=> Perimeter = 2(32.7)

=> Perimeter = 65.4 m

Perimeter of the rectangle = 65.4 m

NOTE:

Some important formulas:

Area of Square = (Side)²

Area of rectangle = Length*Breadth

Area of rhombus = Base*Altitude

Area of parallelogram = Base*Altitude

Area of Triangle = (Base*Altitude)/2

Perimeter of Square = 4(side)

Perimeter of rectangle = 2(length+breadth)